Multiplying Simple Fractions with Reducing Across Fractions
Example
1 Simple Fraction Multiplication with Reducing Across Fractions
| 5 | 1 | |||
| --- | x | --- | = | --- |
| 4 | 5 |
Before multiplying the numerators and denominators, look for ways to reduce across both fractions. This is also called cancellation. This means to see if a numerator and a denominator can be divided by a common factor or reduced. In this example the 5 of the first numerator can be reduced with the 5 of the second denominator. The result is both numbers being changed to 1 as follows:
| 5/5 | 1 | |||
| --- | x | --- | = | --- |
| 4 | 5/5 |
| 1 | 1 | 1 | ||
| --- | x | --- | = | --- |
| 4 | 1 | 4 |
Then you will not have to reduce your answer.
The answer in simplest form is 1/4.
Example
2 Simple Fraction Multiplication with Reducing Across Fractions
Several Times
| 2 | 9 | |||
| --- | x | --- | = | --- |
| 3 | 18 |
Before multiplying the numerators and denominators, look for ways to reduce across both fractions. This means to see if a numerator and a denominator can be divided by a common factor or reduced. In this example the 2 of the first numerator can be reduced with the 18 of the second denominator. The result is:
| 2/2 | 9 | |||
| --- | x | --- | = | --- |
| 3 | 18/2 |
The problem 2/3 times 9/18 becomes:
| 1 | 9 | |||
| --- | x | --- | = | --- |
| 3 | 9 |
Look for other ways to reduce across both fractions. This means to see if a numerator and a denominator can be divided by a common factor or reduced. In this example the 3 of the first denominator can be reduced with the 9 of the second numerator. The result is:
| 1 | 9/3 | |||
| --- | x | --- | = | --- |
| 3/3 | 9 |
The problem 1/3 times 9/9 now becomes:
| 1 | 3 | |||
| --- | x | --- | = | --- |
| 1 | 9 |
You are not allowed to cancel two denominators with each other.
Look for another way to reduce across fractions. This means to see if a numerator and a denominator can be divided by a common factor or reduced. In this example the 3 of the second numerator can be reduced with the 9 of the second denominator. The result is:
| 1 | 3/3 | |||
| --- | x | --- | = | --- |
| 1 | 9/3 |
The problem 1/1 times 3/9 now becomes:
| 1 | 1 | 1 | ||
| --- | x | --- | = | --- |
| 1 | 3 | 3 |
After all of the reducing or cancelling the final answer is 1/3.
You will not have to reduce your answer since you cancelled out as much as possible.
The answer in simplest form is 1/3.